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CLASS XII MATHEMATICS CHAPTER 5

Continuity and Differentiability

Complete Class XII Mathematics chapter notes covering limits, continuity, differentiability, derivatives, chain rule, implicit differentiation, logarithmic differentiation, parametric differentiation and second-order derivatives.

CBSE Pattern Limits Continuity Differentiability Chain Rule Implicit Differentiation
(a, f(a)) Tangent x y f(x), continuity & differentiation
01
Chapter Overview

Introduction

Continuity and Differentiability is one of the fundamental chapters of Class XII Mathematics. The concepts of limit, continuity and derivative form the foundation of differential calculus.

Continuity describes whether a function behaves without a break at a point, while differentiability describes whether the function has a well-defined instantaneous rate of change or slope.

∼

Limit

Describes the value approached by a function.

✓

Continuity

No break or jump at the point.

m

Derivative

Measures instantaneous rate of change.

02
Foundation

Limits

The limit of a function describes the value that the function approaches as the independent variable approaches a particular value.

limx → a f(x) = L

Left-Hand Limit

limx → a⁻ f(x)

Right-Hand Limit

limx → a⁺ f(x)

Existence of Limit

The two-sided limit exists only when the left-hand limit and right-hand limit are equal and finite.

LHL = RHL = L   ⇒   limx→af(x)=L
a L f(x) approaches L x → a
03
Core Concept

Continuity

A function f(x) is continuous at x = a if:

1. f(a) is defined
2. limx→af(x) exists
3. limx→af(x) = f(a)

Fundamental Condition

limx→a f(x) = f(a)

Continuity from Left and Right

limx→a⁻f(x) = f(a) = limx→a⁺f(x)
(a, f(a)) Continuous Curve

Example

Check whether f(x)=x²+3x+2 is continuous at x = 1.

f(1)=1+3+2=6
limx→1(x²+3x+2) = 1+3+2 = 6

Therefore, limx→1f(x)=f(1).

Hence the function is continuous at x = 1.

04
Important Results

Properties of Continuity

If f and g are continuous at x = a, then the following functions are also continuous at x = a, wherever they are defined.

f(x) + g(x)

Sum of continuous functions

f(x) − g(x)

Difference of continuous functions

f(x)g(x)

Product of continuous functions

f(x) / g(x)

Quotient when g(a) ≠ 0

Standard Continuous Functions

Polynomial, rational functions on their domains, exponential, logarithmic, trigonometric and inverse trigonometric functions are continuous wherever they are defined.

05
Core Concept

Differentiability

A function is differentiable at x = a if its derivative exists at x = a.

f′(a) = limh→0 [f(a+h) − f(a)] / h

Left-Hand Derivative

LHD = limh→0⁻ [f(a+h) − f(a)] / h

Right-Hand Derivative

RHD = limh→0⁺ [f(a+h) − f(a)] / h

Differentiability Condition

LHD = RHD = f′(a)
Tangent at x = a Derivative = slope of tangent
06
Important Relationship

Continuity and Differentiability

Differentiability

⇒

Continuity

If f is differentiable at a point, then f must be continuous at that point.

Continuity

⇏

Differentiability

A function may be continuous but not differentiable at a point.

Differentiability ⇒ Continuity

Standard Example

The function f(x)=|x| is continuous at x = 0 but is not differentiable there because its left-hand and right-hand derivatives are different.

07
Derivative Rules

Derivatives

Important Standard Derivatives

d/dx (xⁿ) = nxⁿ⁻¹
d/dx (sin x) = cos x
d/dx (cos x) = −sin x
d/dx (tan x) = sec²x
d/dx (cot x) = −cosec²x
d/dx (sec x) = sec x tan x
d/dx (cosec x) = −cosec x cot x
d/dx (eˣ) = eˣ
d/dx (aˣ) = aˣ ln a
d/dx (ln x) = 1/x

Product Rule

d/dx [uv] = u dv/dx + v du/dx

Quotient Rule

d/dx (u/v) = [v du/dx − u dv/dx] / v²
08
Composite Functions

Chain Rule

The chain rule is used when one function is composed with another function.

If y = f(g(x)), then

dy/dx = df/dg × dg/dx
x u = g(x) y = f(u) g f Multiply the rates

Example

Find the derivative of:

y = sin(x²)
Let u = x²
y = sin u

dy/du = cos u
du/dx = 2x

Therefore,
dy/dx = cos u × 2x
= 2x cos(x²)
09
Advanced Differentiation

Implicit Differentiation

When x and y are related by an equation and y is not explicitly expressed as a function of x, differentiation is performed implicitly.

d/dx (y) = dy/dx

Important Rule

Whenever a term containing y is differentiated, multiply by dy/dx.

Example

x² + y² = 25
Differentiating both sides:

2x + 2y dy/dx = 0

2y dy/dx = −2x

dy/dx = −x/y
10
Powerful Technique

Logarithmic Differentiation

Logarithmic differentiation is useful when a variable occurs in both the base and exponent, or when a function contains products and quotients that are difficult to differentiate directly.

y = f(x)

Taking logarithm:
ln y = ln f(x)

Example

y = xˣ
Taking logarithm:
ln y = x ln x

Differentiating:
(1/y) dy/dx = ln x + 1

Therefore:
dy/dx = y(ln x + 1)

Since y = xˣ,
dy/dx = xˣ(ln x + 1)
11
Parametric Form

Parametric Differentiation

If x and y are both expressed in terms of a parameter t, then:

x = f(t),    y = g(t)
dy/dx = (dy/dt) / (dx/dt)

Important Condition

The formula requires dx/dt ≠ 0 at the point under consideration.

Example

x = t²,    y = t³
dx/dt = 2t
dy/dt = 3t²

Therefore,
dy/dx = (3t²)/(2t)

dy/dx = 3t/2   (t ≠ 0)
12
Higher Derivatives

Second Order Derivatives

If y=f(x), then the first derivative is dy/dx. Differentiating it again gives the second derivative.

First derivative: y′ = dy/dx

Second derivative: y″ = d²y/dx²

Example

y = x⁴ − 3x² + 5x
y′ = 4x³ − 6x + 5

Therefore,
y″ = 12x² − 6
y = f(x) y′ y″ Function Rate of change Change of rate
13
Step-by-Step Practice

Solved Examples

Example 1 — Check continuity of a polynomial
f(x) = x³ − 2x + 1

Polynomial functions are continuous for every real number.

Therefore f(x) is continuous for all x ∈ ℝ.

Example 2 — Find a parameter for continuity
f(x) =
ax + 1,   x < 2
5,   x = 2
x + a,   x > 2

For continuity at x = 2:

LHL = 2a + 1
RHL = 2 + a
f(2) = 5

Hence:

2a + 1 = 5
a = 2

The required value is a = 2.

Example 3 — Differentiate sin(x²)
y = sin(x²)
Using chain rule:
dy/dx = cos(x²) × 2x

dy/dx = 2x cos(x²)
Example 4 — Product Rule
y = x² sin x
Let u = x², v = sin x

y′ = u v′ + v u′

= x² cos x + 2x sin x
Example 5 — Implicit differentiation
x² + xy + y² = 7
2x + (x dy/dx + y) + 2y dy/dx = 0

(x + 2y)dy/dx = −(2x+y)

dy/dx = −(2x+y)/(x+2y)
Example 6 — Logarithmic differentiation
y = (x² + 1)ˣ
ln y = x ln(x² + 1)

(1/y)dy/dx = ln(x²+1) + x(2x)/(x²+1)

Therefore:
dy/dx = (x²+1)ˣ [ln(x²+1) + 2x²/(x²+1)]
Example 7 — Parametric differentiation
x = a cos t,    y = a sin t
dx/dt = −a sin t
dy/dt = a cos t

Therefore:
dy/dx = (a cos t)/(−a sin t)

dy/dx = −cot t
Example 8 — Second derivative
y = x⁵ − 4x³ + 2x
y′ = 5x⁴ − 12x² + 2

y″ = 20x³ − 24x
Example 9 — Test differentiability of |x| at 0
f(x) = |x|
LHD at x = 0 = −1
RHD at x = 0 = 1

Since LHD ≠ RHD,

f(x)=|x| is not differentiable at x=0.

However, it is continuous at x=0.

Example 10 — Derivative of tan⁻¹x
y = tan⁻¹x
dy/dx = 1/(1+x²)
14
Self Assessment

Practice Questions

1. Find lim(x→2) (x²+3x+1).
Answer: 15
2. Check whether f(x)=x²−4x+7 is continuous at x=2.
Answer: Yes. Every polynomial function is continuous for all real x.
3. Find the derivative of x⁷.
Answer: 7x⁶
4. Differentiate sin(3x).
Answer: 3cos(3x)
5. Differentiate cos(x²).
Answer: −2x sin(x²)
6. Differentiate x²eˣ.
Answer: eˣ(x²+2x)
7. Differentiate ln(x²+1).
Answer: 2x/(x²+1)
8. Find dy/dx if x²+y²=16.
Answer: dy/dx = −x/y
9. Find dy/dx if x=t² and y=t³.
Answer: dy/dx = 3t/2, t≠0
10. Find the second derivative of x⁴.
Answer: 12x²
11. Is |x| differentiable at x=0?
Answer: No. LHD = −1 and RHD = 1.
12. State the relation between differentiability and continuity.
Answer: Differentiability at a point implies continuity at that point.
13. Differentiate tan⁻¹x.
Answer: 1/(1+x²)
14. Differentiate sec x.
Answer: sec x tan x
15. Differentiate xˣ using logarithmic differentiation.
Answer: xˣ(ln x+1)
16. Find d²y/dx² for y=x³−5x.
Answer: 6x
17. Find the derivative of e^(2x+1).
Answer: 2e^(2x+1)
18. Find dy/dx for x=a cos t, y=a sin t.
Answer: −cot t
19. State the continuity condition at x=a.
Answer: lim(x→a)f(x)=f(a)
20. State the differentiability condition at x=a.
Answer: LHD = RHD = f′(a)
15
Higher Order Thinking

HOT Questions

1. Find the value of k for which the function is continuous at x=1:
f(x)=
kx+2, x<1
5, x=1
x+k, x>1

Equate LHL, RHL and f(1).

2. Show that every differentiable function is continuous.

Start with the definition of derivative and write:

f(a+h)-f(a) = h × [f(a+h)-f(a)]/h

Taking h→0 proves that f(a+h)→f(a), hence continuity.

3. Find the value of a for which |x−a| is differentiable at x=a.

At x=a the graph has a corner. Compare the left and right derivatives.

The function is not differentiable at x=a.

4. If x=t+1/t and y=t−1/t, find dy/dx.
dx/dt = 1 − 1/t²
dy/dt = 1 + 1/t²

Therefore:
dy/dx = (1+1/t²)/(1−1/t²)
5. Find the derivative of y=(sin x)ˣ.
ln y = x ln(sin x)

(1/y)y′ = ln(sin x)+x cot x

Therefore:
y′=(sin x)ˣ [ln(sin x)+x cot x]
6. Find d²y/dx² for y=sin x.
y′ = cos x
y″ = −sin x
7. Determine whether the function x|x| is differentiable at x=0.

For x≥0, x|x|=x² and for x<0, x|x|=−x².

LHD = 0,    RHD = 0

Hence it is differentiable at x=0.

8. Find the condition for continuity of a piecewise function.

At every joining point, equate:

LHL = RHL = f(a)
16
Last Minute Revision

Quick Revision Sheet

Concept Important Formula / Result
Limit lim(x→a) f(x)
Limit Exists LHL = RHL
Continuity lim(x→a)f(x)=f(a)
Differentiability LHD = RHD
Derivative from First Principle f′(a)=lim(h→0)[f(a+h)-f(a)]/h
Product Rule (uv)′=uv′+vu′
Quotient Rule (u/v)′=(vu′−uv′)/v²
Chain Rule dy/dx=(dy/du)(du/dx)
Implicit Differentiation d(y)/dx = dy/dx
Parametric Differentiation dy/dx=(dy/dt)/(dx/dt)
Second Derivative d²y/dx²
Key Relation Differentiability ⇒ Continuity
Limit Continuity Derivative Higher Derivatives approach no break slope rate of change
17
Board Examination

Exam Tips

01

Check the point

Always identify the point where continuity or differentiability is being tested.

02

Continuity

Write LHL = RHL = f(a).

03

Differentiability

Compare LHD and RHD at piecewise or modulus functions.

04

Use Chain Rule

For composite functions, identify the inner and outer functions.

05

Implicit Functions

Remember to multiply differentiated y-terms by dy/dx.

06

Parametric Form

Use dy/dx = (dy/dt)/(dx/dt).

07

Logarithmic Differentiation

Take logarithms when the variable occurs in both base and exponent.

08

Show Working

Write intermediate steps clearly to avoid losing marks.

CHAPTER 5 CHECKLIST Limits Continuity Differentiability Chain Rule Implicit Parametric Practice formulas + piecewise functions + application-based questions
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